WordPress建网站：如何调用当前文章的前5篇和后5篇（wordpress自定义html）

function ztmao_get_post( $previous = true, $number = 1 ) {     //global当前文章变量 $post 和数据库操作类wpdb         global $post, $wpdb;     if (emptyempty( $post ) )         return null;     $current_post_date = $post->post_date;//当前文章的时间         $join = ;     $posts_in_ex_cats_sql = ;     //加入表         $join = " INNER JOIN $wpdb->term_relationships AS tr ON p.ID = tr.object_id INNER JOIN $wpdb->term_taxonomy tt ON tr.term_taxonomy_id = tt.term_taxonomy_id";     //获取当前文章所属分类,可以同属多个分类,如果是自定义的分类法,将category换成对应的分类法即可     $cat_array = wp_get_object_terms($post->ID, level, array(fields => ids));     $join .= " AND tt.taxonomy = level AND tt.term_id IN (" . implode(,, $cat_array) . ")";     //判断时间是大于还是小于         $op = $previous ? < : >;     //排序         $order = $previous ? DESC : ASC;     $where = $wpdb->prepare("WHERE p.post_date $op %s AND p.post_type = %sAND p.post_status = publish ", $current_post_date, $post->post_type);     $sort  = "ORDER BY p.post_date $order LIMIT 0, $number";     $query = "SELECT p.* FROM $wpdb->posts AS p $join $where $sort";     $query_key = adjacent_post_ . md5($query);     $result = wp_cache_get($query_key, counts);     if ( false !== $result )         return $result;     $result = $wpdb->get_results("SELECT p.* FROM$wpdb->posts AS p $join $where $sort");     if ( null === $result )         $result = ;     wp_cache_set($query_key, $result, counts);     return $result; }

<h4>前几篇文章</h4>             <ul>             <?php             $preposts = v7v3_get_post(true,3);             foreach( $preposts as $postt ){                 echo <li><a href=".get_permalink($postt->ID)." title=".$postt->post_title .">.$postt->post_title .</a></li>;             };             ?>             </ul>             <h4>后几篇文章</h4>             <ul>             <?php             $nextposts = ztmao_get_post(false,3);             foreach( $nextposts as $postt ){                 echo <li><a href=".get_permalink($postt->ID)." title=".$postt->post_title .">.$postt->post_title .</a></li>;             };             ?>             </ul>